Plaksha Previous Year Cutoff 2024-25: Qualifying (Shortlist), Final (Call)

The cutoff criteria for Admission in Plaksha University, Mohali, Punjab is as follows:

- Candidates must have completed their 10+2 or equivalent examination from a recognized board with minimum 60% marks in aggregate.

- Candidates must have cleared JEE Main/ UGC NET/ SET/ CAT/ XAT/ CMAT/ GMAT entrance examination with minimum 60% marks.

- Candidates must have a valid score in the Plaksha University admission test.

Admission to Plaksha University is based on the cutoff criteria set by the university. The cutoff criteria for admission to the engineering program is a minimum of 60% marks in 10+2 with Physics, Chemistry, and Mathematics as compulsory subjects. For admission to the business program, the cutoff criteria is a minimum of 50% marks in 10+2 with English as a compulsory subject.

Plaksha University is a new-age, research-focused university located in Mohali, Punjab. The university offers a variety of undergraduate and graduate programs in the fields of Technology, Business, and Design. Admission to Plaksha University is based on merit, and students are required to meet certain cutoff criteria in order to be eligible for admission.

The cutoff criteria for admission to Plaksha University vary depending on the program and course of study. For example, the cutoff marks for admission to the B.Tech program is 80% for General category students and 75% for SC/ST category students. Similarly, the cutoff marks for admission to the MBA program is 70% for General category students and 60% for SC/ST category students.

To be eligible for admission to Plaksha University, students must have completed their 10+2 or equivalent examination from a recognized board or university with the minimum required marks. In addition, they must also have cleared any entrance examination conducted by the University.